Abstract
In this note we show by a simple direct proof that Folkman's necessary and sufficient condition for an infinite family of sets with finitely many infinite members to have a transversal implies Woodall's condition. A short proof of Folkman's theorem results by combining with Woodall's proof.
Item Type: | Journal article |
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Faculties: | Mathematics, Computer Science and Statistics > Computer Science |
Subjects: | 500 Science > 510 Mathematics |
URN: | urn:nbn:de:bvb:19-epub-8383-8 |
ISSN: | 0095-8956 |
Language: | English |
Item ID: | 8383 |
Date Deposited: | 11. Dec 2008, 15:09 |
Last Modified: | 13. Aug 2024, 12:50 |