Abstract
In this note we show by a simple direct proof that Folkman's necessary and sufficient condition for an infinite family of sets with finitely many infinite members to have a transversal implies Woodall's condition. A short proof of Folkman's theorem results by combining with Woodall's proof.
| Item Type: | Journal article |
|---|---|
| Faculties: | Mathematics, Computer Science and Statistics > Computer Science |
| Subjects: | 500 Science > 510 Mathematics |
| URN: | urn:nbn:de:bvb:19-epub-8383-8 |
| ISSN: | 0095-8956 |
| Language: | English |
| Item ID: | 8383 |
| Date Deposited: | 11. Dec 2008 15:09 |
| Last Modified: | 13. Aug 2024 12:50 |

